1 条题解
-
0
C++ :
#include<bits/stdc++.h> using namespace std; int n; string s, tmp; struct dictionary { string a, b; } Q[102]; int main() { cin >> n; for (int i = 1; i <= n; i++)cin >> Q[i].a >> Q[i].b; cin >> s; s += '0'; for (int i = 0; i < s.length(); i++) { if (s[i] >= 'a' && s[i] <= 'z')tmp += s[i]; else { if (s[i - 1] >= 'a' && s[i - 1] <= 'z') {//在多重标点时不用判断 int flag = 0; for (int j = 1; j <= n; j++) { if (tmp == Q[j].a) { tmp = Q[j].b; flag = 1; break; } } if (flag == 0)cout << "UNK"; else { cout << tmp; } tmp = "";//将字符串清空 } if (s[i] != '0')cout << s[i]; } } return 0; }
- 1
信息
- ID
- 5533
- 时间
- 1000ms
- 内存
- 128MiB
- 难度
- (无)
- 标签
- 递交数
- 0
- 已通过
- 0
- 上传者